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Java Strings Introduction
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62 lines (44 loc) · 1.9 KB
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/*
The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.
Given two strings of lowercase English letters, and , perform the following operations:
Sum the lengths of and .
Determine if is lexicographically larger than (i.e.: does come before in the dictionary?).
Capitalize the first letter in and and print them on a single line, separated by a space.
Input Format
The first line contains a string . The second line contains another string . The strings are comprised of only lowercase English letters.
Output Format
There are three lines of output:
For the first line, sum the lengths of and .
For the second line, write Yes if is lexicographically greater than otherwise print No instead.
For the third line, capitalize the first letter in both and and print them on a single line, separated by a space.
Sample Input 0
hello
java
Sample Output 0
9
No
Hello Java
Explanation 0
String is "hello" and is "java".
has a length of , and has a length of ; the sum of their lengths is .
When sorted alphabetically/lexicographically, "hello" precedes "java"; therefore, is not greater than and the answer is No.
When you capitalize the first letter of both and and then print them separated by a space, you get "Hello Java".
*/
import java.io.*;
import java.util.*;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
String A=sc.next();
String B=sc.next();
int len=A.length()+B.length();
System.out.println(len);
if(A.compareTo(B)>0)
{
System.out.println("Yes");
}
else
System.out.println("No");
System.out.println(Character.toUpperCase(A.charAt(0))+A.substring(1)+" "+Character.toUpperCase(B.charAt(0))+B.substring(1));
}
}